Based on the following information: A series of chemicals were added to some AgNO3(aq). NaCl(aq) was added first to the silver nitrate solution with the end result shown below in test tube 1, NH3(aq) was then added with the end result shown in test tube 2, and HNO3(aq) was added last with the end result shown in test tube 3.

Please write the balanced equation for each of the three tubes. Thanks!

1 Ag^+(aq) + Cl^-(aq) --> AgCl(s)

2 AgCl(s) + 2NH3(aq) → Ag(NH3)2+(aq) + Cl-(aq)
3 NH3(aq) + H+(aq) → NH4+(aq)
4 Ag^+(aq) + Cl^-(aq) --> AgCl(s)

To write the balanced equations for each of the three test tubes, we need to determine the chemical reactions that occur when the chemicals are added.

1. Test Tube 1: NaCl(aq) + AgNO3(aq)
The chemical reaction between sodium chloride and silver nitrate produces a precipitate of silver chloride (AgCl) and soluble sodium nitrate (NaNO3). The balanced equation for this reaction is:
NaCl(aq) + AgNO3(aq) -> AgCl(s) + NaNO3(aq)

2. Test Tube 2: AgCl(s) + NH3(aq)
The addition of ammonia to silver chloride forms a complex ion known as silver ammonia complex (Ag(NH3)2+). The balanced equation for this reaction is:
AgCl(s) + 2NH3(aq) -> Ag(NH3)2+(aq) + Cl-(aq)

3. Test Tube 3: Ag(NH3)2+(aq) + HNO3(aq)
The reaction between the silver ammonia complex and nitric acid results in the formation of silver nitrate (AgNO3) and the release of ammonia gas (NH3). The balanced equation for this reaction is:
Ag(NH3)2+(aq) + HNO3(aq) -> AgNO3(aq) + NH3(g) + H2O(l)

These are the balanced equations for the three test tubes based on the given information.

To write the balanced equations for each test tube reaction, we need to determine the products formed in each case. Let's start with the information provided.

In test tube 1, NaCl(aq) was added to the silver nitrate solution (AgNO3(aq)). We can determine the products by using double replacement (also known as precipitation) reaction rules. Sodium chloride (NaCl) is a soluble compound, so it dissociates into its respective ions in water, Na+ and Cl-. Similarly, silver nitrate (AgNO3) also dissociates into Ag+ and NO3- ions.

The reaction can be written as:

AgNO3(aq) + NaCl(aq) -> AgCl(s) + NaNO3(aq)

Thus, the balanced equation for test tube 1 is:

AgNO3(aq) + NaCl(aq) -> AgCl(s) + NaNO3(aq)

Moving on to test tube 2, NH3(aq) was added to the previous reaction mixture. Ammonia (NH3) is a weak base, and when added to silver chloride (AgCl), it forms a precipitate of a complex ion called silver diamine ion (Ag(NH3)2+). The nitrate ion (NO3-) remains unchanged.

The reaction can be written as:

AgCl(s) + 2NH3(aq) -> Ag(NH3)2+(aq) + Cl-(aq)

Hence, the balanced equation for test tube 2 is:

AgCl(s) + 2NH3(aq) -> Ag(NH3)2+(aq) + Cl-(aq)

Finally, in test tube 3, HNO3(aq) is added to the mixture. Nitric acid (HNO3) is a strong acid and completely dissociates in water into H+ and NO3- ions. The silver diamine ion (Ag(NH3)2+) reacts with nitric acid to produce silver nitrate (AgNO3) and release ammonia (NH3) back into solution.

The reaction can be written as:

Ag(NH3)2+(aq) + HNO3(aq) -> AgNO3(aq) + NH3(aq) + H2O(l)

Therefore, the balanced equation for test tube 3 is:

Ag(NH3)2+(aq) + HNO3(aq) -> AgNO3(aq) + NH3(aq) + H2O(l)

In summary, the balanced equations for each test tube reaction are as follows:

Test tube 1: AgNO3(aq) + NaCl(aq) -> AgCl(s) + NaNO3(aq)
Test tube 2: AgCl(s) + 2NH3(aq) -> Ag(NH3)2+(aq) + Cl-(aq)
Test tube 3: Ag(NH3)2+(aq) + HNO3(aq) -> AgNO3(aq) + NH3(aq) + H2O(l)