How many mg of Ca^2+ are in one mEq?
What I did was
mg = mEq x mol weight / valence
mg = 1 x 40.078/ 2 = 20 mg
Is this correct?
It looks ok to me although I did it another way.
!eq = 40/2 = 20 g
1 meq = 0.020 g = 20 mg.
What I did was
mg = mEq x mol weight / valence
mg = 1 x 40.078/ 2 = 20 mg
Is this correct?
!eq = 40/2 = 20 g
1 meq = 0.020 g = 20 mg.