A parallelogram has the area of a 507 square centimeters, and its height is 3 times its base. What are the base and height?
solVe for b; then use h = 3b
507 = b h = 3 b^2
Solve for b; then use h = 3b.
ur mom
The area of a rectangle is
507
centimeters squared. The length is
3
times the width.
To find the base and height of the parallelogram, we can make use of the formula for the area of a parallelogram, which is given as:
Area = base × height
We are given that the area of the parallelogram is 507 square centimeters. Let's denote the base as 'b' and the height as 'h'.
Given that the height is 3 times the base, we can write the equation:
h = 3b
Now, substituting this value of the height into the formula for the area, we get:
507 = b × 3b
507 = 3b^2 [Expanding]
We can rearrange this equation to solve for 'b'. Divide both sides of the equation by 3:
507/3 = b^2
169 = b^2 [Dividing]
Now, taking the square root of both sides, we find:
b = √169
b = 13 [The square root of 169 is 13]
So, the base of the parallelogram is 13 centimeters.
To find the height, we substitute the value of the base into the equation for the height:
h = 3b
h = 3 × 13
h = 39
Therefore, the height of the parallelogram is 39 centimeters.