Let matrix p= [6 -4]
1 0
If where a and b are real numbers, I is a identity matrix and 0 is a null matrix, find a and b.
To find the values of a and b in the given matrix equation:
p = [6 -4; 1 0]
We can compare the corresponding elements of both matrices. The given equation suggests that:
6 = a + b
-4 = -a
From the second equation, we can deduce that a = 4. Substituting this value into the first equation:
6 = 4 + b
Now, we can solve for b:
2 = b
Therefore, a = 4 and b = 2.