Is this right?!
G(x)=x^3+2 ; x=-2.-1.0,1,2
g(-2) ; -2^3+2=-6
g(-1) ; -1^3+2=1
g(0) ; 0^3+2=2
g(1) ; 1^3+2=3
g(2) ; 2^3+2=10
looks good to me.
Thanks very much!
just a note you should write
g(-2) = (-2)^3+2 = -6
you are correct only because (-2)^3 = -2^3
for even powers, such as 2, (-2)^2 ≠ -2^2
Lol. Ahh yes I know. I found that mistake. and corrected it too.
Thank you though.
Yes, you have correctly evaluated the function G(x) for the given values of x.
To evaluate G(x) for each value of x, we substitute the given values of x into the function G(x) and perform the calculations.
Let's go through each calculation step-by-step:
1. g(-2): To evaluate g(-2), substitute x = -2 into the function G(x):
G(-2) = (-2)^3 + 2
= -8 + 2
= -6
2. g(-1): To evaluate g(-1), substitute x = -1 into the function G(x):
G(-1) = (-1)^3 + 2
= -1 + 2
= 1
3. g(0): To evaluate g(0), substitute x = 0 into the function G(x):
G(0) = (0)^3 + 2
= 0 + 2
= 2
4. g(1): To evaluate g(1), substitute x = 1 into the function G(x):
G(1) = (1)^3 + 2
= 1 + 2
= 3
5. g(2): To evaluate g(2), substitute x = 2 into the function G(x):
G(2) = (2)^3 + 2
= 8 + 2
= 10
Therefore, your answers for g(-2), g(-1), g(0), g(1), and g(2) are -6, 1, 2, 3, and 10, respectively.