# math

3
---
2
---------
1 + 1
-- --
3 x

I assume you mean (3/2)/[(1/3) + (1/x)]
You could rewrite the denominator as
[(1/3) + (1/x)] = (x + 3)/(3x)
(3/2)/[(1/3) + (1/x)]
= (3/2)*(3x)/(x+3)= (9/2)[x/(x+3)]

Thank you

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