what would be the chart to use for carbon 14 whcih has a half life of 5730 years and a piece of wood which originally has 12 grams pf radioactive isotope; If the half lives occurred and now has 0.75 grams left?

To calculate the number of half-lives and determine the time elapsed, we can use the half-life formula:

N = N₀ * (1/2)^(t/t₁/₂)

Where:
- N is the final amount of the substance,
- N₀ is the initial amount of the substance,
- t is the time elapsed,
- t₁/₂ is the half-life of the substance.

In this case, we know that N₀ is 12 grams, N is 0.75 grams, and t₁/₂ is 5730 years. We need to find the value of t.

Let's rearrange the equation to solve for t:

t = t₁/₂ * log(N/N₀) / log(1/2)

Now let's substitute the values:

t = 5730 * log(0.75/12) / log(1/2)

Using a scientific calculator, calculate the natural logarithm (log) of 0.75 divided by 12, then divide it by the natural logarithm of 1/2. This will give you the value of t in years.

After obtaining the value of t, you can use this information to construct a chart showing the amount of carbon-14 over time. The x-axis would represent time in years, and the y-axis would represent the amount of carbon-14 in grams. You can plot data points at various time intervals to demonstrate the decay of carbon-14 over time.