H6P6: Urbium Oxide
First Part of the Question:
Urbium (Ur) is an upscale element found in big cities. Its oxide (UrO2) is not very stable and decomposes readily at temperatures exceeding 66∘ C. The figure below shows how the rate of reaction varies with the concentration of UrO2 at 75∘ C.
The rate r is in units of M⋅s−1 and the concentration c of UrO2 is in units of M (mole⋅L−1). The slope has a value of 1.34 and the intercept has a value of 1.51. What is the order of reaction for the decomposition of urbium oxide?
Second part of the Question:
Select the graph below that best represents how the rate of reaction varies with concentration of urbium oxide at 100∘ C (red) compared with the rate versus concentration at 75∘ C (black).
A)
B)
C)
D)
second part = B
Noted.
Any idea for The first part?
The first part:
1.34
Thank you!
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To determine the order of reaction for the decomposition of urbium oxide (UrO2), we need to analyze the figure provided which shows the rate of reaction (r) versus the concentration (c) of UrO2 at 75∘C.
First, we need to understand the rate equation for the reaction. The rate equation is typically of the form: r = k * [UrO2]^m, where k is the rate constant and m is the order of reaction.
Looking at the figure, we can see that the rate equation is linear, meaning the relationship between r and c is a straight line. This suggests that the order of reaction, m, is likely a whole number.
To find the order of reaction, we can look at the slope of the line in the figure. The slope is given as 1.34. The order of reaction, m, is equal to the slope of the line.
Therefore, the order of reaction for the decomposition of urbium oxide is 1.
Moving on to the second part of the question, we need to select the graph that best represents how the rate of reaction varies with concentration of urbium oxide at 100∘C (red) compared with the rate versus concentration at 75∘C (black).
Since the four graphs are not provided as options, it's not possible to accurately determine which one best represents the comparison. To answer this part, we would need to see and analyze the four given graphs.