Tigger jumps into the sandpit. As this 13 kg animal jumps up, his initial velocity is 6 m/s with an angle of 26 degrees. As Tigger lands into the sandpit, how much work is done by the sand to stop him? Answer in units of Joules

To calculate the work done by the sand to stop Tigger, we can use the work-energy principle. The work done on an object is equal to the change in its kinetic energy.

The initial kinetic energy of Tigger can be calculated using the formula: KE = 1/2 * mass * velocity^2.

First, let's calculate the initial kinetic energy:
KE_initial = 1/2 * 13 kg * (6 m/s)^2

Next, to find the work done by the sand, we need to find the final kinetic energy of Tigger as he lands into the sandpit. Since Tigger comes to a complete stop, his final kinetic energy is zero.

Now, we can calculate the work done by the sand:
Work = KE_final - KE_initial = 0 - KE_initial
= - KE_initial

Substituting the values:
Work = - 1/2 * 13 kg * (6 m/s)^2

Now we can evaluate the expression to find the work done by the sand:
Work = - 1/2 * 13 kg * (6 m/s)^2
= - 1/2 * 13 kg * 36 m^2/s^2
= - 234 Joules

Therefore, the work done by the sand to stop Tigger is -234 Joules. The negative sign indicates that the sand performs work in the opposite direction to Tigger's motion, effectively slowing him down.