i am less than 200 the sum of my digits is 18 i have 3 digits i am an even number what am i.
HELP ME PLEASE THANK YOU ABBIGAIL
1st digit is obviously 1
so, the other digits add to 17. Only 8 and 9 can do that
the number is even, so the last digit must be 8.
198
thank you!!!!
To find the answer to this question, we can simplify the information given and use a systematic approach:
1. You are looking for a three-digit even number, which means the hundreds digit can be any number from 1 to 9.
2. The sum of the digits is 18, which means that the sum of the hundreds, tens, and units digits is 18.
3. Let's start by assuming the hundreds digit is 1 and find the other two digits that satisfy the constraints:
- If the hundreds digit is 1, the remaining two digits should add up to 17.
- Since you are looking for an even number, the units digit must be an even number.
- Starting with the largest even number possible, which is 8, let's test if this works:
- If the units digit is 8, the tens digit should be 9, since 9 + 8 = 17.
- So, the number would be 198.
- However, 198 is not less than 200, so this assumption does not work.
4. Now, let's move on to the next possible hundreds digit, which is 2, and repeat step 3:
- If the hundreds digit is 2, the remaining two digits should add up to 16.
- Since the units digit must be even, let's try the largest even number possible, which is 8:
- If the units digit is 8, the tens digit should be 8, since 8 + 8 = 16.
- So, the number would be 288.
- 288 is less than 200, and the sum of its digits is 18, satisfying all the given conditions.
5. Therefore, the answer to the question is 288.
In summary, the three-digit even number that is less than 200, has a digit sum of 18, and satisfies all the given conditions is 288.