what dimensions would make a box that has a volume of 27? show how you came up with it?
The cube root of 27 is 3.
3 x 3 x 3 = 27 ----- Ms Sue's answer
or
1 x 3 x 9 = 27
or
1/2 x 3 x 18 = 27
or
2.5 x 2 x 5.4 = 27
As you can see there would be an infinite number of solutions to your problem.
I would say the question is poorly worded
To find the dimensions of a box with a volume of 27, we need to consider that the volume of a box is calculated by multiplying its length, width, and height.
Let's assume the length of the box is represented by L, the width by W, and the height by H.
So, the volume equation can be written as:
Volume = L * W * H
Given that the volume is 27, we can substitute this value into the equation:
27 = L * W * H
To find the possible dimensions, we need to think about the factors of 27. Factors are numbers that divide evenly into another number without leaving a remainder.
The factors of 27 are: 1, 3, 9, and 27.
Now, let's try different combinations of these factors:
- L = 1, W = 1, H = 27
(1 * 1 * 27 = 27)
- L = 1, W = 3, H = 9
(1 * 3 * 9 = 27)
- L = 1, W = 9, H = 3
(1 * 9 * 3 = 27)
- L = 1, W = 27, H = 1
(1 * 27 * 1 = 27)
- L = 3, W = 1, H = 9
(3 * 1 * 9 = 27)
- L = 3, W = 3, H = 3
(3 * 3 * 3 = 27)
- L = 3, W = 9, H = 1
(3 * 9 * 1 = 27)
- L = 9, W = 1, H = 3
(9 * 1 * 3 = 27)
- L = 9, W = 3, H = 1
(9 * 3 * 1 = 27)
- L = 27, W = 1, H = 1
(27 * 1 * 1 = 27)
These are all the possible combinations that satisfy the volume equation. Therefore, the dimensions of the box with a volume of 27 can be any of the following:
- 1 unit by 1 unit by 27 units
- 1 unit by 3 units by 9 units
- 1 unit by 9 units by 3 units
- 1 unit by 27 units by 1 unit
- 3 units by 1 unit by 9 units
- 3 units by 3 units by 3 units
- 3 units by 9 units by 1 unit
- 9 units by 1 unit by 3 units
- 9 units by 3 units by 1 unit
- 27 units by 1 unit by 1 unit