0.2688 of a monoprotic acid neutralizes 16.4mL 0f 0.08133 M KOH. Calculate the molar mass of the acid in units of g/mol
0.2688 what? grams?
HA + KOH ==> KA + H2O
mols KOH = M x L = ?
mols HA = mols KOH (look at the coefficients in the balanced equation.)
mols = grams/molar mass. You know mols and grams, solve for molar mass.
To calculate the molar mass of the acid, we can use the given information about the volume and concentration of the KOH solution and the amount of acid that neutralized it.
Step 1: Calculate the number of moles of KOH used.
The volume (V) of 0.08133 M KOH solution used is 16.4 mL, which is 0.0164 L.
The concentration (C) is 0.08133 M.
Using the formula: moles = volume * concentration
moles of KOH = 0.0164 L * 0.08133 M = 0.001334 mol
Step 2: Set up a chemical equation for the neutralization reaction between the acid and KOH.
The balanced equation for the reaction is as follows:
Acid + KOH → Salt + Water
Step 3: Determine the ratio between the acid and KOH in the balanced equation.
From the balanced equation, we can see that the ratio between the acid and KOH is 1:1. This means that 0.001334 mol of the acid was used.
Step 4: Calculate the molar mass of the acid.
The molar mass can be calculated using the formula: molar mass = mass of substance / number of moles
mass of acid = 0.2688 * molar mass of acid
Rearranging the formula to solve for the molar mass: molar mass of acid = mass of acid / (0.2688 * moles of acid)
Substituting the values: molar mass of acid = mass of acid / (0.2688 * 0.001334)
The mass of the acid can be calculated by multiplying the volume of the KOH solution used by its concentration, and then adjusting for the ratio of acid to KOH in the balanced equation:
mass of acid = (16.4 mL * 0.08133 M) / 1
Substituting the values: molar mass of acid = [(16.4 mL * 0.08133 M) / 1] / (0.2688 * 0.001334)
Calculating the molar mass of the acid using this equation will give you the answer in units of g/mol.
To calculate the molar mass of the acid, we'll need to use the equation:
Molarity (M) = moles (mol) / volume (L)
First, let's calculate the number of moles of KOH used in the reaction:
Molarity of KOH (M1) = 0.08133 M
Volume of KOH (V1) = 16.4 mL = 16.4 / 1000 L = 0.0164 L
Now, we can calculate the number of moles of KOH:
moles of KOH (mol1) = Molarity (M1) × Volume (V1)
= 0.08133 M × 0.0164 L
= 0.001334 mol
According to the reaction equation, the ratio between the moles of KOH and the moles of the acid is 1:1. Since we know the moles of KOH used, we can say that the moles of the acid used are also 0.001334 mol.
Now, we'll use the mass of the acid (in grams) and the moles of the acid to calculate its molar mass.
mass (g) = moles (mol) × molar mass (g/mol)
mass (g) = 0.2688 × molar mass (g/mol)
Therefore, we can rewrite the equation as:
molar mass (g/mol) = mass (g) / moles (mol)
molar mass (g/mol) = (0.2688 g) / (0.001334 mol)
molar mass (g/mol) ≈ 201.35 g/mol
Therefore, the molar mass of the acid is approximately 201.35 g/mol.