Could someone please explain the steps in finding all the real zeroes
y=(x-12)^3-7
I do not know how
you want
(x-12)^3 - 7 = 0
(x-12)^3 = 7
x-12 = ∛7
x = 12 + ∛7
Sure, I'd be happy to help!
Finding the real zeroes of a function involves finding the values of x for which the function equals zero. In this case, we have the function:
y = (x-12)^3 - 7
To find the real zeroes, we set y = 0 and solve for x. Let's do that:
0 = (x-12)^3 - 7
Now, let's isolate the term with the cube:
(x-12)^3 = 7
To remove the cube, we take the cube root of both sides:
∛((x-12)^3) = ∛7
Simplifying, we get:
x - 12 = ∛7
To isolate x, we add 12 to both sides:
x = 12 + ∛7
Therefore, the only real zero of the function is x = 12 + ∛7.
I hope that helps! Let me know if you have any more questions.
To find all the real zeros of the given function y=(x-12)^3-7, we can follow the steps below:
Step 1: Set the given function equal to zero.
0 = (x-12)^3 - 7
Step 2: Add 7 to both sides of the equation.
7 = (x-12)^3
Step 3: Take the cube root on both sides of the equation.
∛7 = x-12
Step 4: Add 12 to both sides of the equation.
x = 12 + ∛7
Hence, the only real zero of the given function is x = 12 + ∛7.
To find all the real zeros of a function, you need to find the x-values that make the function equal to zero (y=0). In this case, we have the function y=(x-12)^3-7.
Step 1: Set y=0.
Since we are looking for the x-values that make the function equal to zero, we set y=0:
0 = (x-12)^3-7
Step 2: Add 7 to both sides of the equation.
By adding 7 to both sides, we isolate the term with the cube:
7 = (x-12)^3
Step 3: Take the cube root of both sides.
Taking the cube root will eliminate the cube and leave us with just (x-12):
∛7 = x - 12
Step 4: Add 12 to both sides.
By adding 12 to both sides, we isolate the x:
x = ∛7 + 12
Therefore, the real zero of the function y=(x-12)^3-7 is x = ∛7 + 12.