A 25.0 g block of copper at 350.0 degrees celcius has 857J of heat added to it. What is the final temperature of the block of copper?
q = mass Cu x specific heat Cu x (Tfnal-Tinitial)
q = 857 J. Substitute and solve for Tf.
To find the final temperature of the block of copper, you need to use the specific heat capacity of copper and apply the formula for heat transfer.
The formula for heat transfer is:
Q = mcΔT
Where:
Q = heat transferred (in joules)
m = mass of the substance (in grams)
c = specific heat capacity of the substance (in J/g°C)
ΔT = change in temperature (in °C)
In this case, you are given:
Q = 857 J
m = 25.0 g
c (specific heat capacity of copper) = 0.39 J/g°C (approximately)
ΔT = final temperature - initial temperature
First, rearrange the formula to solve for ΔT:
Q = mcΔT
ΔT = Q / (mc)
Substitute the given values into the formula:
ΔT = 857 J / (25.0 g * 0.39 J/g°C)
By calculating the numerator and denominator separately:
ΔT = 857 J / 9.75 J/°C
ΔT = 87.95 °C
Now, to find the final temperature, add the change in temperature (ΔT) to the initial temperature (350.0 °C):
Final temperature = 350.0 °C + 87.95 °C
Final temperature = 437.95 °C
Therefore, the final temperature of the block of copper is approximately 437.95 °C.