A cubical object of sides 5 cm is immersed completely in water. What is the force of buoyancy on the object? (Assume g = 10 m/s2)
The buoyancy force equals the weight of 125 cm^3 of water. Multiply that mass (0.125 kg) by g.
A cubical object of sides 5 cm is immersed completely in water. What is the force of buoyancy on the object? (Assume g = 10 m/s2)
To calculate the force of buoyancy on an object, we need to use Archimedes' principle, which states that the buoyant force acting on an object immersed in a fluid is equal to the weight of the fluid displaced by the object.
In this case, the cubical object is completely immersed in water. Since water is the fluid, we need to determine the volume of water displaced by the object.
The volume of a cube is given by the formula:
Volume = side length^3
In this case, the side length of the cube is 5 cm, which is equivalent to 0.05 meters (since 1 meter = 100 cm). So, the volume of the cube is:
Volume = (0.05 m)^3 = 0.05 m * 0.05 m * 0.05 m = 0.000125 m^3
Next, we need to calculate the weight of the water displaced by the cube. The density of water is approximately 1000 kg/m^3, which means that each cubic meter of water weighs 1000 kg.
So, the weight of the water displaced by the cube is:
Weight = density * volume * gravity
Weight = 1000 kg/m^3 * 0.000125 m^3 * 10 m/s^2 (since g = 10 m/s^2)
Weight = 1.25 kg
Finally, the force of buoyancy acting on the cube is equal to the weight of the water displaced, which is 1.25 kg. Therefore, the force of buoyancy on the object is 1.25 kg or 12.5 N (since F = ma and a = g).