Please help asap, (Question) he length width of a rectangle are in the ratio 3:2. The perimeter is seventy-three centimters.
What is your question?
Let L= 3x and B = 2x.
P = 2L + 2B
73= 2(3x)+2(2x)
73= 6x+4x
73= 10x
or x = 73/10
x = 7.3 cm
Now, L = 3x= 3(7.3)=21.9 cm
and B = 2x= 2(7.3)=14.6 cm
To solve this problem, we need to find the lengths of the sides of the rectangle. Here's how you can approach it:
Step 1: Let's assume the length of the rectangle is 3x, and the width is 2x, where x is a common ratio.
Step 2: The formula for the perimeter of a rectangle is: Perimeter = 2(Length + Width).
So, in this case, the formula becomes: 73 = 2(3x + 2x).
Step 3: Simplify the equation: 73 = 2(5x). Divide both sides of the equation by 2 to isolate x: 73/2 = 5x.
Step 4: Solve for x: x = 73/(2*5) = 7.3.
Step 5: Now that we have the value of x, we can find the length and width of the rectangle by substituting it back into our assumptions.
Length = 3x = 3 * 7.3 = 21.9 cm.
Width = 2x = 2 * 7.3 = 14.6 cm.
So, the length of the rectangle is 21.9 cm, and the width is 14.6 cm.