two equal charges exert an elecrtric force on each other of 0.0385N when positioned 0.15m apart determine the magnitude of the charge on each point.

F=kq^2/d^2 coulombs law

q=sqrt( F*d^2/k)

To determine the magnitude of the charge on each point, we can use Coulomb's law, which states that the electric force between two charges is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance between them.

Coulomb's law equation is:

F = k * (q1 * q2) / r^2

Where:
F is the electric force between the charges,
k is the electrostatic constant (9 x 10^9 Nm^2/C^2),
q1 and q2 are the magnitudes of the charges,
r is the distance between the charges.

Given that the electric force is 0.0385 N (which represents the magnitudes of the charges), and the distance between them is 0.15 m, we can rearrange the equation to solve for the magnitude of the charges:

0.0385 N = (9 x 10^9 Nm^2/C^2) * (q1 * q2) / (0.15 m)^2

Simplifying the equation:

0.0385 N * (0.15 m)^2 = (9 x 10^9 Nm^2/C^2) * (q1 * q2)

Now, let's calculate:

q1 * q2 = (0.0385 N * (0.15 m)^2) / (9 x 10^9 Nm^2/C^2)

q1 * q2 = (0.0385 N * 0.0225 m^2) / (9 x 10^9 Nm^2/C^2)

q1 * q2 = 8.6625 x 10^-12 C^2

To find the magnitude of each charge, we need to divide this value by 2 since the charges are equal:

q1 = q2 = √(8.6625 x 10^-12 C^2) / 2

q1 = q2 = √(8.6625 x 10^-12) / √2

q1 = q2 = 2.95 x 10^-6 C

Therefore, the magnitude of each charge is approximately 2.95 x 10^-6 C.