There are 3 gardens below. They are all joined. Garden A and C are are perfect squares. A is 121 m2 and C is 169 m2. What is the area of garden B? Label all the dimensions and then find the perimeter of the entire three gardens that are joined together?

All I know is that 11x11 = 121 and 13x13 = 169
PLEESE HELP .. THANKS

A is 11 by 11

B is 11 by 13
c is 13 by 13
total area is 433 m2
area of B is 143 m2
total perimeter is 96 m

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To find the area of garden B, we need to know the dimensions of the garden. Since garden A is a perfect square with an area of 121 m², we can find its side length by taking the square root of the area:

Side length of garden A = √121 = 11 meters

Similarly, since garden C is a perfect square with an area of 169 m², its side length is:

Side length of garden C = √169 = 13 meters

Now, because gardens A, B, and C are all joined, we know that the sides of garden B are connected to the sides of gardens A and C. Thus, the side length of garden B is the difference between the side lengths of gardens A and C:

Side length of garden B = Side length of garden C - Side length of garden A
= 13 meters - 11 meters
= 2 meters

Now that we know the side length of garden B, we can calculate its area:

Area of garden B = (Side length of garden B)²
= 2 meters × 2 meters
= 4 m²

So, the area of garden B is 4 m².

To find the perimeter of all three gardens joined together, we add up the lengths of all the sides.

Perimeter of garden A = 4 × (Side length of garden A)
= 4 × 11 meters
= 44 meters

Perimeter of garden B = 4 × (Side length of garden B)
= 4 × 2 meters
= 8 meters

Perimeter of garden C = 4 × (Side length of garden C)
= 4 × 13 meters
= 52 meters

Total perimeter = Perimeter of garden A + Perimeter of garden B + Perimeter of garden C
= 44 meters + 8 meters + 52 meters
= 104 meters

Therefore, the perimeter of the entire three gardens joined together is 104 meters.