what is the force per meter on a wire carrying 7.5A current when perpendicular to a 0.70T field?
what if the angle between the wire and the field is 45 degree?
Ampere’s force
F=ILBsinα
F(ℓ)=F/L=IBsinα=7.5•0.7•sin45 = ...
To calculate the force per meter on a wire carrying a current in a magnetic field, you can use the formula:
F = BIL
Where:
F is the force
B is the magnetic field strength
I is the current
L is the length of the wire
In this case, the current is 7.5A and the magnetic field strength is 0.70T.
To find the force per meter, we need to know the length of the wire.
Please provide the length of the wire to proceed with the calculation.
To find the force per meter on a wire carrying a current in a magnetic field, you can use the formula:
F = BIL
Where:
F is the force
B is the magnetic field strength
I is the current
L is the length of the wire
In this case, the wire is carrying a current of 7.5A and is perpendicular to a magnetic field strength of 0.70T. However, the length of the wire is not given, so we'll assume that it's one meter (L = 1m).
Now, we can substitute the given values into the formula:
F = (0.70T) * (7.5A) * (1m)
Calculating this gives us:
F = 5.25 N
Therefore, the force per meter on the wire carrying 7.5A current when perpendicular to a 0.70T field is 5.25 Newtons.