How many moles of oxygen are required for the combustion of 25.5 g of magnesium?
To determine the number of moles of oxygen required for the combustion of magnesium, we need to use the balanced chemical equation for the combustion reaction of magnesium.
The balanced chemical equation is:
2 Mg + O2 -> 2 MgO
From the balanced chemical equation, we can see that we need 1 mole of oxygen for every 2 moles of magnesium.
To calculate the number of moles of oxygen required, we first need to calculate the number of moles of magnesium.
The molar mass of magnesium (Mg) is approximately 24.31 g/mol.
To calculate the number of moles of magnesium, we can use the formula:
moles = mass (g) / molar mass (g/mol)
moles of magnesium = 25.5 g / 24.31 g/mol
moles of magnesium = 1.05 mol
Since we need 1 mole of oxygen for every 2 moles of magnesium, we need half as many moles of oxygen.
moles of oxygen = moles of magnesium / 2
moles of oxygen = 1.05 mol / 2
moles of oxygen = 0.525 mol
Therefore, 0.525 moles of oxygen are required for the combustion of 25.5 g of magnesium.
To determine the number of moles of oxygen required for the combustion of magnesium, we need to use the balanced chemical equation for the combustion reaction.
The balanced equation for the combustion of magnesium is:
2 Mg + O2 → 2 MgO
From the equation, we can see that 2 moles of magnesium react with 1 mole of oxygen to form 2 moles of magnesium oxide.
First, we need to convert the mass of magnesium to moles by using its molar mass. The molar mass of magnesium (Mg) is approximately 24.31 g/mol.
Number of moles of magnesium (Mg):
25.5 g Mg × (1 mol Mg/ 24.31 g Mg) = 1.05 mol Mg
According to the balanced equation, 2 moles of magnesium react with 1 mole of oxygen, so the ratio of moles of magnesium to moles of oxygen is 2:1.
Every 2 moles of magnesium requires 1 mole of oxygen. Therefore, we can calculate the moles of oxygen required using the following ratio:
Number of moles of oxygen (O2):
1.05 mol Mg × (1 mol O2/ 2 mol Mg) = 0.525 mol O2
So, 0.525 moles of oxygen are required for the combustion of 25.5 g of magnesium.
write the equation:
2Mg + O2>>2MgO
figure the moles in 25.5g Mg, then half of that number is the number of moles of O2.