How many moles of CO2 would be expected to be produced from 0.00639 moles of sodium carbonate?
Na2CO3 ==> Na2O + CO2
1 mol Na2CO3 produces 1 mol CO2.
So 0.00639 mol Na2CO3 will produce 0.00639 mol CO2 if you have 100% efficiency.
0.00639
To determine the number of moles of CO2 produced from a given amount of sodium carbonate (Na2CO3), we need to consider the balanced chemical equation for the reaction in which sodium carbonate reacts to produce carbon dioxide (CO2).
The balanced chemical equation for the reaction is as follows:
Na2CO3 + HCl -> CO2 + H2O + 2NaCl
From the equation, we can see that 1 mole of sodium carbonate (Na2CO3) reacts to produce 1 mole of carbon dioxide (CO2). Therefore, the number of moles of CO2 produced would be the same as the number of moles of sodium carbonate used.
Given that we have 0.00639 moles of sodium carbonate, we can conclude that 0.00639 moles of carbon dioxide would be expected to be produced.
To determine the number of moles of CO2 produced from a given amount of sodium carbonate, we first need to know the balanced chemical equation for the reaction involved.
The balanced chemical equation for the reaction between sodium carbonate (Na2CO3) and an acid can be represented as:
Na2CO3 + 2HCl -> 2NaCl + CO2 + H2O
According to the equation, one mole of sodium carbonate reacts with two moles of hydrochloric acid (HCl) to produce one mole of CO2.
Given that 0.00639 moles of sodium carbonate are provided, we can use the stoichiometric coefficients from the balanced equation to determine the moles of CO2 produced.
Since the ratio of moles of sodium carbonate to moles of CO2 is 1:1, we can directly infer that 0.00639 moles of sodium carbonate would produce 0.00639 moles of CO2.
Therefore, the expected number of moles of CO2 produced from 0.00639 moles of sodium carbonate is 0.00639 moles.