Could you please show me how to work this problem?
Each hand in the human body has 27 bones. There are 6 more bones in the fingers than in the wrist. There are 3 fewer bones in the palm than in the wrist. How many bones are in each part of the hand?
f = w+6
p = w-3
f+w+p = 27
now make substitutions, or solve using elimination or matrices, to get
(f,p,w) = (14,5,8)
that is,
14 finger
5 palm
8 wrist
Let x be the number of bones in the wrist.Then fingers have x+6 bones and palm has x-3 bones. Altogether there are 27 so; wrist+fingers+palm=27 so x+(x+6)+(x-3)=27 so 3x+3=27 3x=24 x=8 Hence 8 bones in wrist, 8+6=14 bones in fingers and 8-3=5 bones in palm.
We need the answer not a new teacher =_= we came here for a reason that reason was not to learn =_=
Sure! Let's break down the problem step by step to find the number of bones in each part of the hand.
Step 1: Define the variables.
Let's denote the number of bones in the wrist as "W".
The number of bones in the fingers will be "W + 6" since there are 6 more bones in the fingers than in the wrist.
The number of bones in the palm will be "W - 3" since there are 3 fewer bones in the palm than in the wrist.
Step 2: Set up the equation.
We know that the total number of bones in both hands is 27. Since each hand has the same number of bones, we can write the equation as:
2W + (W + 6) + (W - 3) = 27
Step 3: Solve the equation.
Now, we can simplify the equation and solve for W:
2W + W + 6 + W - 3 = 27
4W + 3 = 27
4W = 27 - 3
4W = 24
W = 24/4
W = 6
Step 4: Calculate the number of bones in each part.
Now that we have found the number of bones in the wrist (W = 6), we can calculate the number of bones in the fingers and the palm.
The number of bones in the fingers is W + 6 = 6 + 6 = 12
The number of bones in the palm is W - 3 = 6 - 3 = 3
So, in each hand, there are:
- 6 bones in the wrist
- 12 bones in the fingers
- 3 bones in the palm.
I hope this helps! Let me know if you have any further questions.