Light intensity of water equation log I/12=-0.0125
What depth will the light intensity be half that of surface?
your equation is confusing. What is log I/12 ?
log intensity over 12
To find the depth at which the light intensity is half that of the surface, we can use the given equation log(I/12) = -0.0125, where I represents the light intensity at a certain depth.
First, we need to rearrange the equation to isolate I. We can do this by taking the exponential of both sides:
e^(log(I/12)) = e^(-0.0125)
Using the property of logarithms, e^(log(I/12)) simplifies to I/12:
I/12 = e^(-0.0125)
Next, we can multiply both sides of the equation by 12 to isolate I:
I = 12 * e^(-0.0125)
Now that we have the equation for I, we can determine the depth at which the light intensity is half that of the surface (I = I₀/2, where I₀ represents the intensity at the surface). Let's substitute I with I₀/2:
I₀/2 = 12 * e^(-0.0125)
To find the depth, we need to determine the value of I₀. Usually, the intensity of light decreases exponentially with depth, so we need to know the specific value of I₀ for the surface.
Without knowing the value of I₀, it is not possible to calculate the exact depth at which the light intensity is half that of the surface.