How would you prepare 150ml of .5M NaOH starting with a 6M solution of NaOH
To prepare 150ml of 0.5M NaOH solution starting with a 6M solution of NaOH, you would need to dilute the 6M solution with the appropriate amount of water. Here's how you can calculate the required volumes:
Step 1: Determine the dilution factor.
The dilution factor is the ratio of the final volume to the initial volume. In this case, the final volume is 150ml and the initial volume is unknown. We can use the dilution equation:
C1V1 = C2V2
Where:
C1 = initial concentration (6M)
V1 = initial volume (unknown)
C2 = final concentration (0.5M)
V2 = final volume (150ml)
Step 2: Rearrange the equation to solve for V1.
V1 = (C2 x V2) / C1
V1 = (0.5M x 150ml) / 6M
V1 = 7.5ml
Step 3: Calculate the volume of the 6M NaOH solution required.
You will need 7.5ml of the 6M NaOH solution.
Step 4: Calculate the volume of water required.
To achieve a total final volume of 150ml, you will need to add water to make up the remaining volume.
Volume of water = Final volume - Volume of 6M NaOH solution
Volume of water = 150ml - 7.5ml
Volume of water = 142.5ml
So, to prepare 150ml of 0.5M NaOH solution starting with a 6M NaOH solution, you need to mix 7.5ml of the 6M NaOH solution with 142.5ml of water.