3 Cl2 + 6 KOH go toKClO3 + 5 KCl + 3 H2O
How many moles of potassium chlorate form when 2 moles of potassium hydroxide react completely?
There is no formula. There is a process. You convert mols of ANYTHING in the reaction to mols of ANY OTHER reactant OR product by using the coefficients in the balanced equation. For this equation, the coefficients tell you that 1 mol Cl2 will react with 6 mol KOH to produce 1 mol KCLO3 and 5 mol KCl and 3 mols H2O. To make that conversion you simply use the conversion factor which is nothing more than the coefficients. Here is how it works.
Suppose we want to know how many mols H2O will be formed from 6 mols Cl2. That's
6 mols Cl2 x (3 mols H2O/3 mol Cl2) = 6 mols H2O.
How many mols KCl would be formed? That's
6 mols Cl2 x (5 mols KCl/3 mol Cl2) = 10 mols KCl.
How many mols KClO3 would be formed?
That's
6 mols Cl2 x (1 mol KClO3/3 mol Cl2) = 2 mols KClO3.
How many mols KClO3 are formed when 16 mols H2O are formed?
That's
16 mols H2O x (1 mol KClO3/3 mols H2O) = 16/3 = 5.33 mols KClO3.
We can make a formula out of it this way.
mols of what is given x (mols in equation of what we want/mols in equation of what we are given). I hope this helps but please follow up if you have any questions.
6 mols KOH will produce 1 mol KClO3; therefore, 2 mols KOH (1/3 of the 6) must produce 1/3 of the 1 mol KClO3. Right?
is there a formula you use to do this promlem?
To determine the number of moles of potassium chlorate formed when 2 moles of potassium hydroxide react completely, we first need to identify the stoichiometry of the reaction.
From the balanced chemical equation:
3 Cl2 + 6 KOH -> KClO3 + 5 KCl + 3 H2O
We can see that the ratio between potassium hydroxide (KOH) and potassium chlorate (KClO3) is 6:1. This means that for every 6 moles of KOH, 1 mole of KClO3 is formed.
Given that we have 2 moles of KOH, we can set up a simple ratio to find the number of moles of KClO3:
(2 moles KOH) x (1 mole KClO3 / 6 moles KOH) = 1/3 moles KClO3
Therefore, when 2 moles of potassium hydroxide react completely, 1/3 mole of potassium chlorate is formed.