A runner is 22 km east and 15 km south of his starting point. How far is he in a direct line from his starting point?
√(22^2 + 15^2) = √709 = 26.627 km
Thank you so much ! :D
Btw related to the question I asked: how long would it take him to return to his starting point in a direct line if he can run at 10 km per hour?
time = distance/speed, so 2.6627 hr
I assume that's what you got, eh?
So I just round it ? Yep thanks
I got 2 hrs and 40 mins approximately right?
Yes Steve I did @ first get 2.66 can u help me?
Looks good to me.
.6666 = 2/3, and 40 min is 2/3 hour.
To find the distance of the runner in a direct line from his starting point, we can use the Pythagorean theorem. The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
In this case, the distance east and south can be considered as the two sides of the right triangle, and we need to calculate the hypotenuse, which represents the direct distance from the starting point.
First, we calculate the squares of the two sides:
Length east = 22 km
Length south = 15 km
Square of length east = 22 km * 22 km = 484 km²
Square of length south = 15 km * 15 km = 225 km²
Now, we add these two squares:
484 km² + 225 km² = 709 km²
To find the length of the hypotenuse, we take the square root of the sum:
√(709 km²) ≈ 26.66 km
Therefore, the runner is approximately 26.66 km away from his starting point in a direct line.