if 58.44 g of sodium chloride is dissolved in 0.5 liter of water what is the molarity of the sodium chloride solution? The molar mass of sodium chloride is 58.44 grams per mole.
so you have one mole in half a liter which is 2 moles per liter
Molarity=number of moles(n)/volume
also n=mass(m)/molar mass(M)
therefore,
Molarity(C)=mass/molar mass*volume
C=58.44g/0.5L(58.44g/mol)
C=2moles per litre
To find the molarity of a solution, you need to determine the number of moles of solute dissolved in a given volume of solvent. In this case, the solute is sodium chloride (NaCl) and the solvent is water.
First, convert the given mass of NaCl (58.44 g) to moles. Since the molar mass of NaCl is also given as 58.44 g/mol, the mass in grams is equal to the number of moles:
Number of moles = Mass of NaCl / Molar mass of NaCl
= 58.44 g / 58.44 g/mol
= 1 mole
Next, determine the volume of the solution in liters. The given volume is 0.5 liter.
Now, calculate the molarity using the formula:
Molarity = Moles of solute / Volume of solution (in liters)
Molarity = 1 mole / 0.5 L
= 2 moles/L
Therefore, the molarity of the sodium chloride solution is 2 moles per liter (2 M).