Mathematics

A Ladder AB, of length 13m, rests against a vertical wall with its foot on a horizontal floor at a distance of 5meters from the wall. When the top of the ladder slips down a distance x meters on the wall, the foot of the ladder moves out x meters. Find x.

(I couldn't find this answer, can anyone please please help me. With the math equation too? Not the answer only please. So I know what to do it. Thx.)

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  1. It is like triangle.
    a^2+b^2=c^2
    you know that one of the side and hyp. so, you can find the ohter by pluging in like this:
    5^2+b^2= 13^2
    25+b^2=169
    b^2=144
    b= 12

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  2. Actually, it is calculus of differentials.

    C^2=a^2 + b^2
    Take the differential
    2C dC=2a da + 2b db
    but dC is zero (C is held constant), so

    da=- (b/a)db
    so whatever one side slips down the wall, so the other side slips along the floor in the ratio cited.

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    bobpursley

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