A solution containing 80g of NaNO3 in 75g of H2O at 50 degrees celsius is cooled to 20 degrees celsius.

A. how many grams of NaNO3 remain in solution at 20 degrees celsius?
B. How many grams of solid in NaNO3 crystallized after cooling?

To determine the grams of NaNO3 remaining in solution at 20 degrees Celsius and the grams of solid NaNO3 crystallized, we need to consider the solubility of NaNO3 in water at both 50 degrees Celsius and 20 degrees Celsius.

A. To find the grams of NaNO3 remaining in solution at 20 degrees Celsius, we can calculate the solubility of NaNO3 at this temperature using the solubility data.

According to the solubility data, the solubility of NaNO3 at 50 degrees Celsius is approximately 87.6g/100g H2O, and the solubility at 20 degrees Celsius is approximately 32.0g/100g H2O.

Since the solution initially contains 80g of NaNO3 and 75g of H2O, we can compare the mass of NaNO3 in solution at 50 degrees Celsius with the solubility at 20 degrees Celsius.

(80g NaNO3) x (32.0g NaNO3 / 87.6g H2O) = 29.0g NaNO3

Therefore, approximately 29.0 grams of NaNO3 remain in solution at 20 degrees Celsius.

B. To find the grams of solid NaNO3 crystallized after cooling, we can subtract the grams of NaNO3 remaining in solution at 20 degrees Celsius from the initial amount of NaNO3.

(80g NaNO3) - (29.0g NaNO3) = 51.0g NaNO3

Therefore, approximately 51.0 grams of NaNO3 crystallized as a solid upon cooling.

To answer these questions, we'll need to know the solubility of NaNO3 at different temperatures. The solubility of most substances increases as temperature increases, which means more NaNO3 can dissolve in water at higher temperatures.

To find the solubility of NaNO3 at 50 degrees Celsius, we can consult a solubility chart or look up the information in a reference book or online database. Let's assume that at 50 degrees Celsius, the solubility of NaNO3 is 150g per 100g of water.

A. To calculate the amount of NaNO3 that remains in solution at 20 degrees Celsius, we can use the concept of solubility. Since the solubility changes with temperature, we need to find the amount of NaNO3 that can dissolve in 75g of water at 20 degrees Celsius.

Using proportions, we can set up the following equation:

(150g NaNO3 / 100g H2O) = (x grams NaNO3 / 75g H2O)

Simplifying, we get:

150 * 75 = 100 * x
11250 = 100x
x = 11250 / 100 = 112.5g

Therefore, at 20 degrees Celsius, 112.5 grams of NaNO3 will remain in solution.

B. To find the amount of solid NaNO3 crystallized after cooling from 50 degrees Celsius to 20 degrees Celsius, we can subtract the remaining amount of NaNO3 from the initial amount.

Initial amount of NaNO3 in solution = 80g
Remaining amount of NaNO3 at 20 degrees Celsius = 112.5g

Crystallized amount = Initial amount - Remaining amount
Crystallized amount = 80g - 112.5g = -32.5g

Since the result is negative, it means that there is no solid NaNO3 crystallized after cooling from 50 degrees Celsius to 20 degrees Celsius.

chemistry 101