If C is inversely proportional to T, when C=1/6 and T=4/7, find C when T=10.
the formula is
C= K/T
1/6=K/4/7 <-- I use Cross multiplication
K=4/42
that's all.. I can't continue solving cuz my mind is mess... Please Help!! "_"
1/6=K/(4/7)
K = 1/6 * 7/4 = 7/24
C(T) = (7/24) / T
C(10) = 7/24 / 10 = 7/240
YES!! thanks to your help! @Steve ... My mistake.. I multiplied 6 and 7, the one I should multiply by 6 is 4 not 7.. gee, I always forget it.. Thank you again! :)
To find the value of C when T=10, we can use the concept of inverse proportionality.
In an inverse proportion, the product of the two variables remains constant. In this case, we have C multiplied by T, so we can write the equation as C x T = k, where k is the constant of proportionality.
Given that C=1/6 and T=4/7, we can substitute these values into the equation to find k:
(1/6) x (4/7) = k
To simplify the calculation, we can multiply numerators and denominators first:
(1 x 4) / (6 x 7) = k
4/42 = k
Dividing 4 by 42, we find that k = 1/10.5, which can be further simplified to k = 1/21.
Now that we know the value of k, we can use it to find C when T=10:
C x T = k
C x 10 = 1/21
To isolate C, we divide both sides of the equation by 10:
C = (1/21) / 10
C = 1/210
Therefore, when T=10, C is equal to 1/210.