calculus help please

dy/dx = 2y^2

Integrating...y=2/3 y^3 + C
put 1,-1 into the equation, and solve for C.
Then find the y for x=2

if y= a^uhttp://math2.org/math/integrals/tableof.htm
see exponential functions.

dy/dx=2y^2 and if y=-1 when x=1, then when x=2, y=?

how do i get x in the equation. do i integrate dy/dx because that would be (2/3)y^3 +C.

2)how i would integrate 13^x-11^x.

lets say i integrate 13^x, would that be 13^x*log 13. i know there is a formula for that but i don't remember

  1. 👍 0
  2. 👎 0
  3. 👁 101

Respond to this Question

First Name

Your Response

Similar Questions

  1. confused calc

    dy/dx=2y^2 and if y=-1 when x=1, then when x=2, y=? (you already posted this, but i still don't get it) dy/dx = 2y^2 Integrating...y=2/3 y^3 + C put 1,-1 into the equation, and solve for C c=-1/3 so the equation is y=(2y^3)/3-1/3

    asked by david on December 12, 2006
  2. MATH

    I NEED TO SOLVE FOR Y AND X im getting rele confused on this. ok here is the prob. x+y=5 x-2y=-4 equation 1 x+y=5 equation 2 x-2y=-4 Multiply equation 1 by -1. Add equation 1 to equation 2. The x term cancels. Solve for y. THEN,

    asked by Tony on December 17, 2006
  3. Differential Equations

    x dy/dx + y = 1/y^2, solve using bernoulli's equation. i got to du/dx + (2u)/x = 2x(u)^(-1/2). the u^(-1/2) is obviously a problem if im going to solve it using an integrating factor. if that is not what you yourself have gotten

    asked by Bryant on September 25, 2012
  4. Substitution Method-Plz help

    Use the Substitution method to solve the system of equations. x + y = -4 x - y = 2 solve for x in the second equation. x= y+2 Put that in for x in the first equation: x+y=-4 (y+2) + y = -4 solve for y. Then, x= y+2 i don't get

    asked by Svetlana on October 17, 2006
  5. Differential equation (urgent pls!!!)

    Reduce the differential equation below to an exact equation (X - 2siny + 3)dx -(4siny - 2x + 3)dy=0. The problem here is how to solve for the integrating factor...any help pls?

    asked by BEN on March 4, 2016
  6. subsitution method

    Can some one show me how to use the Substitution method to solve the system of these equations. x + y = -4 x - y = 2 x + y = 10 y = x + 8 on the first set. Solve for either x or y in either equation, then put that value into the

    asked by mike on July 1, 2007
  7. Algebra1!Plz help I have test 2morrow!!!

    so would the new eqaution be... 2x+8=10 then.. 2x=2 x=1? We know that y = x + 8. So if x + y = 10, then x + x + 8 = 10. but what about the y?ANd what do I do afetr that? If you know what x equals, then you can calculate what y

    asked by Sammy on November 4, 2006
  8. Calculus

    Hello, I would greatly appreciate any help that I can have with the following calculus question below. It has to do with separable differential equations. I'm also going to explain what I've done so far, so please bear with me

    asked by Stephen on April 16, 2017
  9. Math

    I have got help from Damon on this question but all I need is help on integrating the answer he gave me into my original equation: y=-15/20.25(x+1.5)^2+0 Here's Damon's help: (x+1.5)(x+1.5) = x^2 + 1.5 x + 1.5 x + (1.5*1.5) = x^2

    asked by Alex on December 4, 2014
  10. Math

    have got help from Damon on this question but all I need is help on integrating the answer he gave me into my original equation: y=-15/20.25(x+1.5)^2+0 Here's Damon's help: (x+1.5)(x+1.5) = x^2 + 1.5 x + 1.5 x + (1.5*1.5) = x^2 +

    asked by Alex on December 4, 2014

More Similar Questions