P: Solve each to four decimal places (x real and 0 in degrees)
5 cos x - 2 = 0, 0<orequalto x < 2pi
cosx = 2/5
x in QI or QIV
x = 21.8014°
x = 360-21.8014 = 338.1986°
If you want answers in °, you should express the domain in °, not radians.
You can easily look up special characters, so you can copy/paste θ, and not use 0.
those are 0 in the question not θ
oops. my bad.
x.(x+2)
5x+3).(x+1)=?
(5x+3)(x+1) = 5x^2 + (5+3)x + 3
= 5x^2 + 8x + 3
Just like 53*11 = 5*10^2 + (5+3)*10 + 3 = 500+80+3 = 583
To solve the equation 5cos(x) - 2 = 0 for x in degrees, we need to isolate the cosine term and then use inverse cosine (also known as arccosine) to find the value of x.
Step 1: Isolate the cosine term.
Start by adding 2 to both sides of the equation:
5cos(x) = 2
Step 2: Solve for cos(x).
Now, divide both sides of the equation by 5:
cos(x) = 2/5
Step 3: Find the arccosine.
Using the inverse cosine function (arccos), apply it to both sides of the equation:
x = arccos(2/5)
Step 4: Convert radians to degrees.
The answer is given in radians, but since the question asks for the answer in degrees, we need to convert it. Since pi radians is equal to 180 degrees, we can multiply the radians value by 180/pi to obtain the equivalent degrees.
Therefore,
x (in degrees) = (arccos(2/5)) * (180/pi)
Now, to solve the equation to four decimal places, you can use a scientific calculator or an online trigonometric calculator to evaluate the expression.