Create a visually appealing image showcasing a small black ant attempting to navigate along a simplified 2-dimension Cartesian coordinate plane (x-axis). The illustration should show its journey in the form of a semi-circle, indicating its movement over a span of 4 seconds. Please ensure that the resulting image does not contain any text.

An ant is crawling along the x-axis such that the graph of its position on the x-axis versus time is a semi-circle. The total distance covered in the 4 sec is

1. 4 m
2. 2 m
3. 2 pie m
4. 4 pie m

Speed is not given.And diameter can not be in seconds, so we can not calculate.

As in the time axis, diameter is 4 unit, therefore, radius is 2 unit.

The radius is also 2 unit in the vertical direction (position axis) ie the maximum distance covered while crawling along positive x axis is 2m and along negative x axis is also 2m. Total distance covered = 2+2= 4m

2m

Ans is 2pie

Because diameter of semicircle is 4
Radius is 2
Area of semicircle pie×r×r/2=2pie

Oh, an ant that loves to dance in semi-circles, how fancy! Well, to find the total distance covered, we can use a little math magic. Since the graph is a semicircle, we can calculate the circumference of the semicircle and divide it by 2.

Now, the circumference of a circle is given by 2πr, where r is the radius. In this case, the radius is 2 meters (since the graph covers 4 seconds). So, the circumference is 2π(2) = 4π meters.

Since we only want half of the distance covered (it's a semi-circle, after all), we divide 4π by 2, which gives us 2π meters.

Hence, the total distance covered by the ant in 4 seconds is 2π meters. So option 3, 2π m, is the correct answer.

That ant surely knows how to groove with circles!

To find the total distance covered by the ant in 4 seconds, we need to calculate the length of the semi-circle.

Since the position of the ant versus time is a semi-circle, we can imagine the ant crawling along the circumference of the circle. The distance traveled by the ant will be equal to the length of the semi-circle.

The formula to calculate the length of a semi-circle is given by:

Length = π * radius

In this case, we need to find the radius of the semi-circle. The radius represents the maximum distance the ant can travel along the x-axis.

From the information given in the problem, we know that the ant crawls along the x-axis. Therefore, the maximum distance it can cover in 4 seconds is when it reaches the maximum point of the semi-circle.

Since the maximum point of the semi-circle represents the radius, we can conclude that the radius is equal to 4 units.

Now, substituting the value of the radius into the length formula, we get:

Length = π * 4 = 4π units

Therefore, the total distance covered by the ant in 4 seconds is 4π units.

So, the correct answer is option 3: 2π m.

depends on the ant's speed

distance = speed * time

all we know is time.