For y(x)=ln(3+x2), find y(6)
vbr{lr<5vvx><f(nn)/.bbn>
vbr<lr><5.12>(9.8)^3
.bbn=%ff
%ff=F(9x)
.bbn=%ff9x
.bbn=.133%tri
.bbn=.tri
t.ri=vbr
v=161.2
b=39.1
r=12.7
Sub in values of vbr
y(6) = ln(3+36) = ln 39 or appr 3.66356
To find the value of y(6) for the function y(x) = ln(3 + x^2), we need to substitute x = 6 into the given function.
Step 1: Write the function y(x) = ln(3 + x^2).
Step 2: Substitute x = 6 into the function: y(6) = ln(3 + 6^2).
Step 3: Calculate the value inside the logarithm: y(6) = ln(3 + 36).
Step 4: Simplify the expression inside the logarithm: y(6) = ln(39).
Therefore, y(6) = ln(39).