Spectrophotometric analysis of commercial aspririn. If the number of moles of sodium salicylate are 8.675x10^-6 what would be the number of moles of Iron (III) Salicylate complex and what would be its concentration. The volume of sodium salicylate used is 1 ml and its concentration is 8.675x10^-3 M.

To determine the number of moles of Iron (III) Salicylate complex and its concentration, we need to use the provided information.

First, let's convert the volume of sodium salicylate from milliliters (ml) to liters (L):

1 ml = 1 × 10^(-3) L

Next, we can use the given concentration and volume of sodium salicylate to calculate the number of moles of sodium salicylate:

Number of moles = concentration × volume

Number of moles = 8.675 × 10^(-3) M × 1 × 10^(-3) L

Number of moles = 8.675 × 10^(-6) mol

Since the reaction between sodium salicylate and Iron (III) forms a 1:1 complex, the number of moles of Iron (III) Salicylate complex would also be 8.675 × 10^(-6) mol.

To find the concentration of the Iron (III) Salicylate complex, we need to consider the final volume of the solution. Let's assume the final volume is V liters.

Since the number of moles of the Iron (III) Salicylate complex is equal to the number of moles of sodium salicylate, we can set up the following equation:

Moles of Iron (III) Salicylate complex = concentration × volume

8.675 × 10^(-6) mol = concentration × V

Rearranging the equation to solve for concentration:

Concentration = (8.675 × 10^(-6) mol) / V

So, the concentration of the Iron (III) Salicylate complex would be (8.675 × 10^(-6) mol) divided by the final volume (V) in liters.