A cylinder with radius of 20 ft is being filled with water at a rate of 2000 ft^3/hour. Find the rate at which the height of the water is increasing.
<vx)-ln[.03]/(l1)<l3>
A shortcut I forgot about until calc III is to make it a function of <vx)
vx=nnx+bbn+c
c(x)=<l.5/.556>
nn(x)
x=nn(.565)
bbn
n=(bb)=.909
c=vvx/.909[pi]^2<nnx>
C=?