How many milliliters of a 0.25 M sucrose solution contain 2.0 grams? The molar mass of sucrose (C12H22O11 ) is 342.3 g/mol.
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How many milliliters of a 0.25 M sucrose solution contain 2.0 grams? The molar mass of sucrose (C12H22O11 ) is 342.3 g/mol.
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To calculate the number of milliliters of a 0.25 M sucrose solution that contain 2.0 grams, you'll need to consider the molar mass of sucrose.
The formula you can use to solve this problem is:
Volume (in mL) = (mass / molar mass) / molarity
First, let's convert the mass of sucrose from grams to moles:
Number of moles of sucrose = mass / molar mass
Number of moles of sucrose = 2.0 g / 342.3 g/mol
Next, we can calculate the volume in milliliters:
Volume (in mL) = (2.0 g / 342.3 g/mol) / 0.25 M
Calculating this gives us the answer.
To determine the volume of a solution containing a given mass of solute, you can use the formula:
Volume (in mL) = (mass (in grams) / molar mass (in g/mol)) / molarity (in mol/L)
In this case, you want to find the volume of a 0.25 M sucrose solution that contains 2.0 grams of sucrose. The molar mass of sucrose is given as 342.3 g/mol.
Substituting the values into the formula:
Volume (in mL) = (2.0 g / 342.3 g/mol) / 0.25 mol/L
First, divide the mass of sucrose by its molar mass:
Volume (in mL) = (0.005831 mol) / 0.25 mol/L
Then, divide the result by the molarity:
Volume (in mL) ≈ 0.02332 L × 1000 mL/L
Calculating, you get:
Volume (in mL) ≈ 23.32 mL
Therefore, 23.32 milliliters of a 0.25 M sucrose solution contain 2.0 grams of sucrose.