When 25.0g of Zn reacts with Hcl, how many L of H2 gas are formed at STP?
To calculate the volume of H2 gas formed at STP, we must first use the balanced chemical reaction:
Zn + 2HCl → ZnCl2 + H2
Next, we need to determine the moles of Zn and HCl reacting:
25.0 g Zn * (1 mol Zn / 65.38 g Zn) = 0.382 mol Zn
Now we can use stoichiometry to find the moles of H2 gas formed:
0.382 mol Zn * (1 mol H2 / 1 mol Zn) = 0.382 mol H2
At STP (standard temperature and pressure), 1 mole of an ideal gas occupies a volume of 22.4 L. So, we can calculate the volume (L) of H2 gas:
0.382 mol H2 * (22.4 L H2 / 1 mol H2) = 8.56 L H2
So, 8.56 L of H2 gas are formed at STP when 25.0g of Zn reacts with HCl.
To find out how many liters of H2 gas are formed when 25.0g of Zn reacts with HCl at STP (Standard Temperature and Pressure), we need to follow these steps:
1. Write the balanced chemical equation for the reaction:
Zn + 2HCl -> ZnCl2 + H2
This equation shows that 1 mole of Zn reacts with 2 moles of HCl to produce 1 mole of H2 gas.
2. Convert the given mass of Zn into moles.
The molar mass of Zn is 65.38 g/mol. By dividing the given mass of 25.0g by the molar mass, we can calculate the number of moles:
Moles of Zn = Mass of Zn / Molar mass of Zn
= 25.0g / 65.38 g/mol
= 0.3826 mol (rounded to four decimal places)
3. Use the stoichiometry of the balanced equation to find the number of moles of H2 produced.
Since the balanced equation tells us that 1 mole of Zn produces 1 mole of H2 gas, the number of moles of H2 gas formed will be equal to the number of moles of Zn:
Moles of H2 = Moles of Zn
= 0.3826 mol
4. Convert moles of H2 gas to liters using the ideal gas law at STP.
At STP, 1 mole of any ideal gas occupies 22.4 liters.
Liters of H2 gas = Moles of H2 x 22.4 L/mol
= 0.3826 mol x 22.4 L/mol
= 8.57 liters (rounded to two decimal places)
Therefore, when 25.0g of Zn reacts with HCl at STP, approximately 8.57 liters of H2 gas are formed.
To calculate the volume of hydrogen gas formed when 25.0g of Zn reacts with HCl at STP, we need to follow these steps:
Step 1: Determine the chemical equation for the reaction.
The chemical equation for the reaction between zinc (Zn) and hydrochloric acid (HCl) is as follows:
Zn + 2HCl -> ZnCl2 + H2
Step 2: Calculate the moles of Zn.
To calculate the moles, use the formula:
moles = mass of Zn / molar mass of Zn
The molar mass of Zn is approximately 65.38 g/mol.
moles of Zn = 25.0 g / 65.38 g/mol
Step 3: Use stoichiometry to determine the moles of H2 produced.
From the balanced chemical equation, we see that the ratio of Zn to H2 is 1:1. Therefore, the moles of H2 produced will be the same as the moles of Zn.
Step 4: Calculate the volume of H2 gas at STP.
At STP (Standard Temperature and Pressure), 1 mole of any ideal gas occupies 22.4 liters. Therefore, the volume of H2 gas can be calculated using the formula:
Volume = moles of H2 * 22.4 L/mol
Now, let's plug in the values to calculate the volume:
Volume = (moles of Zn) * 22.4 L/mol
Using the given mass of Zn (25.0 g) and the molar mass of Zn (65.38 g/mol), we can calculate the moles of Zn:
moles of Zn = 25.0 g / 65.38 g/mol
Substituting this value into the volume formula:
Volume = (moles of Zn) * 22.4 L/mol
Volume = (25.0 g / 65.38 g/mol) * 22.4 L/mol
Step 5: Calculate the volume of H2 gas.
Performing the calculation:
Volume = (25.0 g / 65.38 g/mol) * 22.4 L/mol
Calculating this expression gives the volume of H2 gas generated when 25.0g of Zn reacts with HCl at STP.