A solid has weight of 400g in air and when partly immersed in a liquid , has a weight of 320g. if it has a relative density of 0.80, fine the volume of the solid
Yes, I see my mistake.
Thanks, PUNDRIK.
Relative Density = Specific gravity=0.8
Ds=0.80 * Dw = 0.80*1g/cm^3=0.80g/cm^3 =
Density of the solid.
Vs = 400g / 0.8g/cm^3 = 500 cm^3. = Vol.
of solid.
W(air) - W(liquid) = R.D. * VOLUME 400 - 320 = 0.80 * V V = 80/0.80 => 100 cm3
To find the volume of the solid, we can use the concept of relative density.
Relative density is the ratio of the density of a substance to the density of a reference substance. In this case, we can assume the reference substance is water, which has a relative density of 1.
The formula for relative density is:
Relative Density = Density of Substance / Density of Reference Substance
We are given that the relative density of the solid is 0.80, which means:
0.80 = Density of Substance / Density of Water
To find the volume of the solid, we need to know its density. We can calculate the density using the following formula:
Density = Mass / Volume
We know that the mass of the solid is 400g in air and 320g when partly immersed in a liquid. This weight difference is due to the buoyant force acting on the solid when it is immersed in the liquid. The buoyant force reduces the apparent weight of the solid.
The weight of the liquid displaced by the solid is equal to the weight decrease of the solid when immersed. Therefore, the weight of the liquid displaced is 400g - 320g = 80g.
Now, using the known density of water (1g/cm³), we will calculate the volume of the liquid displaced and link it to the volume of the solid.
Density = Mass / Volume
1g/cm³ = 80g / Volume of Liquid Displaced
Volume of Liquid Displaced = 80cm³
Since the volume of the liquid displaced is equal to the volume of the solid, the volume of the solid is 80cm³.