For the emission spectrum of Be3+, calculate the lowest wavenumber νˉ (in inverse meters) of light produced by electron transitions between n=2, n=3, and n=4.
I don't want to know the answer... Just tell me what I would need to do to work it out :) pls?? X
8.56*10^6
by amar chauhan
that's not an answer!
sry. i meant that that wasn't the explanation for how to do it
concepts??
To calculate the lowest wavenumber (νˉ) of light produced by electron transitions between n=2, n=3, and n=4 in the emission spectrum of Be3+, you would follow these steps:
Step 1: Determine the formula or expression for calculating the wavenumber (νˉ) of light.
The formula for calculating wavenumber is given by νˉ = 1/λ, where λ is the wavelength of light.
Step 2: Convert the wavelength to meters.
Since the wavenumber (νˉ) is given in inverse meters, the wavelength (λ) needs to be converted from meters to meters. It is crucial to use the same unit so that the calculations are consistent.
Step 3: Find the energy difference between the electron transitions.
The energy difference (ΔE) between the initial and final energy states can be calculated using the formula ΔE = E_final - E_initial, where E_final and E_initial are the energy levels of the final and initial states, respectively.
Step 4: Use the energy difference to calculate the wavelength.
The energy difference (ΔE) can be converted to a wavelength (λ) by using the equation ΔE = hc/λ, where h is Planck's constant (6.63 x 10^-34 J∙s) and c is the speed of light (2.998 x 10^8 m/s).
Step 5: Substitute the wavelength into the wavenumber formula.
Using the wavelength (λ) obtained in step 4, substitute it into the wavenumber formula: νˉ = 1/λ, to calculate the wavenumber in inverse meters (m^-1).
Step 6: Repeat steps 3-5 for each electron transition.
For the given problem, there are three electron transitions to consider (n=2 to n=3, n=2 to n=4, and n=3 to n=4). Repeat steps 3-5 for each of these transitions to calculate the wavenumber (νˉ) for each transition.
By following these steps, you will be able to calculate the lowest wavenumber (νˉ) of light produced by electron transitions between n=2, n=3, and n=4 in the emission spectrum of Be3+.