A circular disk of radius 30 cm is rotating with an angular velocity of 2 radians / s. What is the tangential velocity of a point on the rim of the disk? What is its centripetal acceleration?
To find the tangential velocity of a point on the rim of the disk, you can use the formula:
v = r * omega,
where v is the tangential velocity, r is the radius of the disk, and omega is the angular velocity.
In this case, the radius of the disk is given as 30 cm (or 0.3 m), and the angular velocity is given as 2 radians/s. Plugging these values into the formula, we can calculate the tangential velocity:
v = 0.3 m * 2 radians/s = 0.6 m/s.
So, the tangential velocity of a point on the rim of the disk is 0.6 m/s.
To find the centripetal acceleration of a point on the rim of the disk, you can use the formula:
a_c = r * omega^2,
where a_c is the centripetal acceleration.
Again, in this case, the radius of the disk is 0.3 m, and the angular velocity is 2 radians/s. Plugging these values into the formula, we can calculate the centripetal acceleration:
a_c = 0.3 m * (2 radians/s)^2 = 1.2 m/s^2.
So, the centripetal acceleration of a point on the rim of the disk is 1.2 m/s^2.