15. What is the solution of the linear-quadratic system of equations?
{y = x^2 + 5x - 3}
{y - x = 2}
makes no damn sense
does anyone else try to understand this but just can't so you end up cheating?
Try substituting those values, and you will see they do not fit either equation.
looking at the 2nd equation, y = x+2, so
x+2 = x^2+5x-3
x^2 + 4x - 5 = 0
(x+5)(x-1) = 0
x = -5 or 1
so, y = -3 or 3
the solutions are thus (-5,-3)(1,3)
first things first...calm down. yes, its extremely hard. but we go simple approach. y-x=2 implies y=x+2.we substitute that in the first equation to get x+2 = x^2+5x-3 =x^2+4x-5=0.
We factor to get (x-1)(x+5)=0. Thus, x=1, or -5. PLugging in, we get y=-3,3. Thus, (1,3)(-5,-3) are the solutions