Login or Sign Up

Ask a New Question

Which expression is equal to log243

since 243 = 3^5, that would be 5 log3

Similar Questions

log243+log27/log9+log1/18

Top answer: log243 + 3/2 - log18 log(243/18) + 3/2 log(27/2) + 3/2 interesting, but you don't say what you are Read more.
Which statement describes why the system below has no solution?{x+2y=53x+6y=10 A The expression 3x+6y cannot equal both 10 and

Top answer: A The expression 3x+6y cannot equal both 10 and 15. Read more.
Simplify the rational expression. State any restrictions on the variable.(t^2 + t - 6)/(t^2 - 9) (t - 2)/(t-3), t not equal 3, t

Top answer: The simplified rational expression is (t+2)/(t-3), with restrictions t cannot equal 3. Read more.
Evaluate:Log243/120-log54/75+log24/27-log5/2

Top answer: what is log (243*24*75*2/120*54*27*5)= log (1)= 0 Read more.
Log243-log64-log3 with the base 3,2,root3 give me a simplify of these

Top answer: Question: log3 243 - log2 64 + log√3 3 This can also be written as: log3 3^5 - log2 2^6 + log√3 Read more.
for questions 1-2, simplify the rational expression. state any restrictions on the variable. p^2-4p-32/p+4A. -p+8; p not equal-4

Top answer: To simplify the rational expression (p^2-4p-32)/(p+4), we need to factor the numerator. The Read more.
The non-permissible values for the expression -9x+8 divided by -9x^2-55x+56 are?a) x does not equal -8/9 b)x does not equal 8 c)

Top answer: hint: -9x^2-55x+56 = (7+x)(8-9x) Read more.
1. Look in Lesson 2 on the study guide to answer this question: An inequality is a statement that one expression is less than,

Top answer: False Read more.
Write the equation log243(81)=4/5 in exponential form.My answer is 243^4/5=81. Evaluate 9^log9(54). My answer is 6. Are these

Top answer: Yes for the first one 9^log 9 of 54 but base^log same base (x) = x so I get 54 for an answer Read more.
Hi, I have a question regarding simplifying the following expression:(1/x)/((1/3)x^(-2/3)) = 3/3sqrtx The last expression reads

Top answer: multiplying by 1/3 ... (1/x) / [x^(-2/3)] = 1 / [x^(1/3)] multiplying by x^(-2/3) ... 1/x = Read more.