15.0 moles of an ideal gas, at an initial pressure of 3.50 x105 N/m2 and an initial volume of 1.200 m3, undergo a small isothermal expansion to a volume of 1.220 m3. Find the work done by the gas.

To find the work done by the gas during the isothermal expansion, we can use the formula:

Work = nRT * ln(V2/V1)

Where:
- n is the number of moles of the gas
- R is the ideal gas constant (8.314 J/(mol·K))
- T is the temperature (given as constant in this case, since it is an isothermal process)
- ln(V2/V1) is the natural logarithm of the ratio of the final volume (V2) to the initial volume (V1)

Given:
n = 15.0 moles
V1 = 1.200 m^3
V2 = 1.220 m^3

We can plug in these values into the formula to calculate the work:

Work = (15.0 mol) * (8.314 J/(mol·K)) * T * ln(1.220/1.200)

However, the temperature (T) is not provided in the given information. Without the temperature, we cannot directly calculate the work done by the gas. The equation needs temperature to be properly solved.

Please provide the temperature (in Kelvin) to proceed with the calculation.