How can the graph of g(x)=3square root x+3 be obtained from the graph of g(x)= 3 square root x?
A. shift the graph 3 units right
b. shift the graph 3 units up
c. shift the graph 3 units down
d. shift the graph 3 units left
I am having problems with the square roots. Can someone please help!!
the graph was shifted up 3 from the original graph that's all the question wants to know
Ladybug, you often tend to forget to put in brackets, so
if you shift
y = 3√x
" to the left 3 units" (d)
you get y = 3√(x+3)
whereas y = 3√x + 3 would have been "up 3 units" (b)
To understand how the graph of g(x) = 3√x + 3 can be obtained from the graph of g(x) = 3√x, let's break it down step by step:
1. Start with the graph of g(x) = 3√x. This is a basic square root function that opens upwards.
2. The number 3 in front of the square root (3√x) stretches the graph vertically. This means that the graph will become steeper and narrower compared to the original graph.
3. The "+ 3" at the end of the function shifts the graph upwards by 3 units. This means that every point on the graph will be moved 3 units higher along the y-axis.
Putting it all together, we can conclude that to obtain the graph of g(x) = 3√x + 3 from the graph of g(x) = 3√x, we need to:
a. Shift the graph 3 units upwards.
Therefore, the correct answer is (b) shift the graph 3 units up.