a nasty little boy tries to drop a water balloon from the top of a 20 m tall building so it lands next to and splashes an innocent woman standing on the ground below. how long does the woman have to get out of the way?
s = 1/2 at^2
20 = 4.9 t^2
t = 2.02 seconds
To calculate the time the woman has to get out of the way, we need to determine how long it takes for the water balloon to fall from the top of the building (20 m) to the ground.
We can use the equation for time of free fall, which is given by:
t = sqrt((2 * h) / g)
where:
t = time of free fall
h = height (in this case, the height of the building)
g = acceleration due to gravity (approximately 9.8 m/s^2)
Plugging in the values:
t = sqrt((2 * 20) / 9.8)
t = sqrt(40 / 9.8)
t ≈ 1.428 seconds (rounded to three decimal places)
Therefore, the woman has approximately 1.428 seconds to get out of the way before the water balloon lands next to her and splashes.