A 890 mL NaCl solution is diluted to a volume of 1.15 and a concentration of 8.00 . What was the initial concentration?
How do I go about this?
M1V1=M2V2? and if it is how do I replace the variables?
Probably M1V1 = M2V2 BUT you give no units. 1.15 what. concn of 8.00 what.
You call 890 V1 and M1 is what you want.
V2 is 1.15 whatever and 8.00 is M2 whatever. Since V1 is 890 mL you need V2 in mL. Whatever unit the 8.00 is will be that unit in M1.
To find the initial concentration, you can use the formula M1V1 = M2V2, which represents the principle of dilution. Here's how you can apply it to this problem:
1. First, identify the given values:
- Initial volume (V1) = 890 mL
- Final volume (V2) = 1.15 L (convert mL to L by dividing by 1000)
- Final concentration (M2) = 8.00
2. Convert the initial volume to liters:
V1 = 890 mL ÷ 1000 = 0.89 L
3. Plug the given values into the dilution formula:
M1V1 = M2V2
4. Replace the variables with the values:
M1(0.89 L) = (8.00)(1.15 L)
5. Solve the equation for M1:
M1 = (8.00)(1.15 L) ÷ (0.89 L)
6. Calculate M1:
M1 ≈ 10.36
Therefore, the initial concentration of the NaCl solution was approximately 10.36.