calculate the mass of naso4 needed to prepare of 0.5L of 0.15M of solution
0.5L * 0.15moles/L = 0.075 moles * 142g/mole = 10.65 g
To calculate the mass of Na2SO4 needed to prepare 0.5L of a 0.15M solution, you can use the formula:
Mass = Volume x Concentration x Molar mass
1. Start by finding the molar mass of Na2SO4.
- The atomic mass of Sodium (Na) is 22.99 g/mol.
- The atomic mass of Sulfur (S) is 32.07 g/mol.
- The atomic mass of Oxygen (O) is 16.00 g/mol.
Na2SO4 contains two sodium atoms (2 x 22.99), one sulfur atom (32.07), and four oxygen atoms (4 x 16.00).
Molar mass of Na2SO4 = (2 x 22.99) + 32.07 + (4 x 16.00)
2. Calculate the molar mass:
Molar mass of Na2SO4 = 45.98 + 32.07 + 64.00
= 142.05 g/mol
3. Now, apply the formula to calculate the mass of Na2SO4 needed:
Mass = Volume x Concentration x Molar mass
Mass = 0.5 L x 0.15 mol/L x 142.05 g/mol
4. Calculate the mass:
Mass = 0.5 x 0.15 x 142.05
= 10.65 grams
Therefore, you would need approximately 10.65 grams of Na2SO4 to prepare 0.5L of a 0.15M solution.