Lead has a density of 11300 kg/m^3 at 0 degrees celcius. What is the density of lead at 90 degrees celcius?

You will find the volumetric thermal expansion coefficient of lead is 87*10^-6 C^-1

Multiply that by 90 C for the relative volume increase factor,
DeltaV/V = 0.0078

Add that to 1 and take the reciprocal

Density(90)/Density(0) = 0.9922

Finally, multiply that by the density at 0 C

no answer sorry

To find the density of lead at a different temperature, we need to take into account the thermal expansion of the material. The formula to calculate the density at a different temperature is:

Density (at a different temperature) = Density (at reference temperature) / (1 + (alpha * (temperature - reference temperature)))

Where:
- Density (at a different temperature) is the density of the material at the desired temperature.
- Density (at reference temperature) is the density of the material at the reference temperature.
- Alpha is the coefficient of thermal expansion of the material.
- Temperature is the desired temperature.
- Reference temperature is the temperature at which the density is given.

For lead, the coefficient of thermal expansion (alpha) is approximately 0.000029 (1/°C). The reference temperature given is 0 degrees Celsius, and the density at that temperature is 11300 kg/m^3. We want to find the density at 90 degrees Celsius.

Using the formula above, we can calculate the density as follows:

Density (at 90°C) = 11300 kg/m^3 / (1 + (0.000029 * (90 - 0)))

Simplifying the equation:

Density (at 90°C) = 11300 kg/m^3 / (1 + (0.000029 * 90))

Density (at 90°C) = 11300 kg/m^3 / (1 + 0.00261)

Density (at 90°C) = 11300 kg/m^3 / 1.00261

Density (at 90°C) ≈ 11,271.26 kg/m^3

Therefore, the density of lead at 90 degrees Celsius is approximately 11,271.26 kg/m^3.

To find the density of lead at 90 degrees Celsius, we need to consider the thermal expansion coefficient of lead. The formula to calculate the density at a given temperature is:

ρ(T2) = ρ(T1) / (1 + β * (T2 - T1))

Where:
ρ(T2) is the density of lead at the desired temperature (90 degrees Celsius in this case)
ρ(T1) is the density of lead at the reference temperature (0 degrees Celsius in this case)
β is the thermal expansion coefficient of lead, and
(T2 - T1) is the difference between the desired temperature and the reference temperature.

The thermal expansion coefficient of lead is approximately 0.000029 per degree Celsius.

Now let's plug in the values and calculate the density at 90 degrees Celsius:

ρ(90) = 11300 kg/m^3 / (1 + 0.000029 * (90 - 0))
= 11300 kg/m^3 / (1 + 0.000029 * 90)
= 11300 kg/m^3 / (1 + 0.000029 * 90)
= 11300 kg/m^3 / (1 + 0.000029 * 90)
= 11300 kg/m^3 / (1 + 0.00261)
= 11300 kg/m^3 / 1.00261
= 11265.61 kg/m^3

Therefore, the density of lead at 90 degrees Celsius is approximately 11265.61 kg/m^3.