If the detector is capturing 6. 107 photons per second at this wavelength, 1820 nm. what is the total energy of the photons detected in one hour?
I got 2e7 but its wrong
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To calculate the total energy of the detected photons in one hour, we first need to calculate the energy of a single photon at the given wavelength.
The energy of a single photon can be calculated using the equation:
E = hc / λ
Where:
E = Energy of the photon
h = Planck's constant (6.626 x 10^-34 J*s)
c = Speed of light (3.00 x 10^8 m/s)
λ = Wavelength of the photon (in meters)
Given the wavelength of 1820 nm (nanometers), we first convert it to meters by dividing by 10^9:
λ = 1820 nm / 10^9 = 1.82 x 10^-6 m
Now, we can substitute the values into the equation to find the energy of a single photon:
E = (6.626 x 10^-34 J*s) * (3.00 x 10^8 m/s) / (1.82 x 10^-6 m)
E ≈ 1.09 x 10^-19 J
Now that we have the energy of a single photon, we can calculate the total energy of the photons detected in one hour:
Number of photons detected per second = 6.107 photons/s
Number of photons detected in one hour = 6.107 photons/s * 60 s/min * 60 min/hour = 22005.6 photons
Total energy of the detected photons in one hour = Energy of a single photon * Number of photons detected in one hour
Total energy = (1.09 x 10^-19 J/photon) * (22005.6 photons)
Total energy = 2.401 x 10^-15 J
Therefore, the correct total energy of the detected photons in one hour is approximately 2.401 x 10^-15 Joules (J).